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Table 3 Cases for an associated triplet \(L_{t} = \{t_1, t_2, t_3\}\) of a shared solo quartet in recursive equation (2). In each case, the quartet is counted exactly once, as shown in column \(\sum\)

From: Median quartet tree search algorithms using optimal subtree prune and regraft

Case

\(S_4({B} \overset{u^{\uparrow }}{\circ }P, R)\)

\(- \varphi _{u^{\uparrow }}^i\)

\(- \varphi _{u^{\uparrow }}^r\)

\(\varphi _u^o\)

\(\varphi _u^r\)

\(\sum\)

\(L_{t} \subset L_{{B}^\vee _{u}}\) or \(L_{t} \subset {L_{{B}^\vee _{u^{\uparrow }}} \setminus L_{{B}^\vee _{u}}}\) or \(L_t \subset L_{{B}^\wedge _{u^{\uparrow }}}\)

1

0

0

0

0

1

\(L_t \not \subset L_{{B}^\vee _{u}}\), \(L_t \not \subset {L_{{B}^\vee _{u^{\uparrow }}} \setminus L_{{B}^\vee _{u}}}\), and \(L_t \subset L_{{B}^\vee _{u^{\uparrow }}}\)

1

\(-1\)

0

0

1

1

\(L_t \not \subset L_{{B}^\vee _{u}}\), \(L_t \not \subset L_{{B}^\wedge _{u^{\uparrow }}}\), and \(L_t \subset L_{{B}^\vee _{u}} \cup L_{{B}^\wedge _{u^{\uparrow }}}\)

1

0

\(-1\)

0

1

1

\(L_t \not \subset {L_{{B}^\vee _{u^{\uparrow }}} \setminus L_{{B}^\vee _{u}}}\), \(L_t \not \subset L_{{B}^\wedge _{u^{\uparrow }}}\), and \(L_t \subset L_{{B}^\wedge _{u}}\)

1

0

\(-1\)

1

1

1

\(t_1 \in L_{{B}^\vee _{u}}\), \(t_2 \in {L_{{B}^\vee _{u^{\uparrow }}} \setminus L_{{B}^\vee _{u}}}\), and \(t_3 \in L_{{B}^\wedge _{u^{\uparrow }}}\)

0

0

0

0

1

1