Enumerating all maximal frequent subtrees in collections of phylogenetic trees
 Akshay Deepak^{1}Email author and
 David FernándezBaca^{2}
https://doi.org/10.1186/17487188916
© Deepak and FernándezBaca; licensee BioMed Central Ltd. 2014
Received: 30 July 2013
Accepted: 2 June 2014
Published: 18 June 2014
Abstract
Background
A common problem in phylogenetic analysis is to identify frequent patterns in a collection of phylogenetic trees. The goal is, roughly, to find a subset of the species (taxa) on which all or some significant subset of the trees agree. One popular method to do so is through maximum agreement subtrees (MASTs). MASTs are also used, among other things, as a metric for comparing phylogenetic trees, computing congruence indices and to identify horizontal gene transfer events.
Results
We give algorithms and experimental results for two approaches to identify common patterns in a collection of phylogenetic trees, one based on agreement subtrees, called maximal agreement subtrees, the other on frequent subtrees, called maximal frequent subtrees. These approaches can return subtrees on larger sets of taxa than MASTs, and can reveal new common phylogenetic relationships not present in either MASTs or the majority rule tree (a popular consensus method). Our current implementation is available on the web at https://code.google.com/p/mfstminer/.
Conclusions
Our computational results confirm that maximal agreement subtrees and all maximal frequent subtrees can reveal a more complete phylogenetic picture of the common patterns in collections of phylogenetic trees than maximum agreement subtrees; they are also often more resolved than the majority rule tree. Further, our experiments show that enumerating maximal frequent subtrees is considerably more practical than enumerating ordinary (not necessarily maximal) frequent subtrees.
Keywords
Background
A phylogenetic tree is an unordered rooted tree whose leaves are in onetoone correspondence with a set of species (also referred to as taxa); its topology represents the hypothetical evolutionary relationships among these species.
An agreement subtree (AST) for a collection of phylogenetic trees on a common leaf set is a minimal subtree connecting a fixed set of leaves that is homeomorphically included in all of the input trees. A maximal agreement subtree (MXST) is an agreement subtree that is not a subtree of any other agreement subtree. An MXST is a maximum agreement subtree (MAST) if it has the largest number of leaves [1]. MASTs are used, among other things, as a metric for comparing phylogenetic trees [2–4], computing their congruence index [5, 6], to identify horizontal gene transfer events [7], for resolving ambiguity in terraces in phylogenetic tree space [8], and as a consensus approach [9].
The set of all MFSTs is a compact nonredundant summary of the set of all FSTs: every FST is a subtree of one or more MFSTs but every MFST is a subtree of only itself. Thus, every MFST reveals some unique phylogenetic information that is not displayed by any other MFST (or FST).
Despite its potential utility, however, the enumeration of all MFSTs in collections of phylogenetic trees has not, to our knowledge, been studied before.
Here we introduce MFSTMINER, an algorithm for enumerating MXSTs and MFSTs. MFSTMINER enumerates MFSTs over partially overlapping leaf sets as well. We compare MFSTMINER with EVOMINER[10], an algorithm for enumerating all FSTs, and show that enumerating MFSTs can be orders of magnitude faster than enumerating all FSTs. Our current implementation of MFSTMINER, which works for up to 250 leaves and 10000 trees, can be downloaded from https://code.google.com/p/mfstminer/.
Related work
The MAST problem was first studied by Finden and Gordon [1]. Since then, due its utility and inherent complexity, the problem has attracted computational biologists and mathematicians alike. The MAST of two trees can be found in polynomial time; indeed, over the years researchers have developed progressively faster algorithms for the problem [11–13]. Finding the MAST of more than two trees is NPhard in general [11], but is solvable in polynomial time for trees of bounded degree [14, 15].
Although maximal subgraph mining [16, 17] and, in particular, maximal subtree mining [18–20] have received much attention in the data mining literature, a different approach is needed for mining phylogenetic trees. This is because phylogenetic trees possess a special structure — only leaves are labeled and the nonleaf nodes must be of degree two or more — that affects the very definition of a subtree [10, 21]. We defer the formal definitions of phylogenetic trees and subtrees to the Preliminaries, on page 4.
Zhang et al. [21] where the first to study frequent phylogenetic subtree mining. They proposed an algorithm, Phylominer, to mine all frequent subtrees in a collection of phylogenetic trees in time quadratic in the size of the output set. In [10] we proposed a new algorithm EVOMINER for the same task that achieves speedups of up to 100 times or more over Phylominer. Both Phylominer and EVOMINER follow an Apriorilike framework [22]. EVOMINER’s increased speed is the result of an efficient phylogenetic treespecific constanttime candidate generation scheme in the candidate generation step, and a novel fingerprinting based scheme for the downwardclosure operation in the frequency counting step.
Ramu et al. [23] proposed a heuristic for enumerating a subset of all MFSTs called maximum frequent subtrees. A maximum frequent subtree is an FST that has the maximum number of leaves among all FSTs. Their method scales well for large phylogenetic datasets, but does not guarantee the enumeration of all MFSTs. To our knowledge, our work is the first to deal with the problem of mining all MFSTs for phylogenetic trees.
Consensus methods are an oftused alternative to frequent or agreement subtree methods, for summarizing the common information in collections of phylogenetic trees. Among the most popular consensus methods is the majorityrule tree (MRT) [24], defined as follows.
Phylogenetic networks represent evolutionary relationships among taxa via directed graphs. In addition to tree nodes —nodes with only one parent—, they allow hybrid nodes —nodes with two parents. Thus, phylogenetic networks are more expressive than phylogenetic trees [29, 30]. In the same way that agreement trees and majority rule trees extract consensus information in phylogenetic trees, consensus networks[31] represent frequent patterns in phylogenetic networks [32].
Preliminaries
A phylogenetic tree (or, for brevity, simply a tree) is an unordered rooted leaflabeled tree. Leaf labels represent the taxonomic units (species or taxa) under study. An isomorphism between phylogenetic trees includes the labels of the leaves. Phylogenetic trees can also be unrooted [33], but here we deal exclusively with rooted phylogenetic trees. A node is internal if it is not a leaf node. Each internal node must have at least two children. Let ${\mathcal{\mathcal{L}}}_{T}$ denote the leaf label set of tree T, and ψ_{ T } denote the bijection that maps the leaf nodes to their unique labels. For convenience, we refer to the set of leaf nodes by their labels in ${\mathcal{\mathcal{L}}}_{T}$. From this point forward, unless the context requires making a distinction, we will drop the subscripts in ${\mathcal{\mathcal{L}}}_{T}$ and ψ_{ T }, and write and ψ respectively. For the rest of the paper, we assume without loss of generality that the leaf label set consists of distinct integers in the range $\left[1,\left\mathcal{\mathcal{L}}\right\right]$; thus, the labels are ordered. We denote the fact that two trees T_{1} and T_{2} are isomorphic by writing T_{1}≡T_{2}.
Consider a tree T and a set ${\mathcal{\mathcal{L}}}^{\prime}\subseteq {\mathcal{\mathcal{L}}}_{T}$. The restriction of T to ${\mathcal{\mathcal{L}}}^{\prime}$, denoted by $T{}_{{\mathcal{\mathcal{L}}}^{\prime}}$, is the minimal homeomorphic subtree of T connecting the leaves with labels in ${\mathcal{\mathcal{L}}}^{\prime}$ (that is, we start with the minimal subtree of T connecting ${\mathcal{\mathcal{L}}}^{\prime}$, and repeatedly suppress nonroot nodes with at most one child until no such nodes remain). A tree T^{′} is a subtree of T if ${\mathcal{\mathcal{L}}}_{{T}^{\prime}}\subseteq {\mathcal{\mathcal{L}}}_{T}$ and ${T}^{\prime}\equiv T{}_{{\mathcal{\mathcal{L}}}_{{T}^{\prime}}}$. Tree T displays T’ if T’ is a subtree of T.
The depth of a node u in a tree T, denoted depth^{ T }(u), is the number of edges from the root to that node; thus the root node is at depth 0. We denote the lowest common ancestor (LCA) of two nodes u and v in T by LCA^{ T }(u,v). When the tree T is clear from the context, we drop the superscripts. A kleaf tree is a tree with k leaves. A triplet is a 3leaf tree.
Algorithmic framework
We first discuss the algorithm for ASTs/MXSTs because it is simpler (since f=1). We then extend it to FSTs/MFSTs.
We enumerate all MXSTs from the solution space of all ASTs. We show that any kleaf AST can be enumerated by combining two unique (k−1)leaf ASTs with certain properties. We call the kleaf tree a join on the two smaller (k−1)leaf trees. To ensure that the enumeration is efficient, we must address three issues. The first is avoiding redundancy — that is, each MXST should be generated only once.
The second is support estimation. While a kleaf AST is enumerated by joining two unique (k−1)leaf ASTs, the converse is not true, i.e., these two (k−1)leaf ASTs can potentially combine into more than one topology over k leaves. The only way to know if a kleaf AST exists as a result of joining these two (k−1)leaf ASTs is to have a mechanism to test if only one topology is supported across all input trees. The third issue is limiting combinatorial explosion. The total number of ASTs can be exponentially larger than the total number of MXSTs. Thus, we need a way to prune the search space of ASTs during enumeration of MXSTs. We describe how we address these issues next.
Nonredundant enumeration
To avoid generating multiple isomorphic copies of the same tree, we enumerate subtrees in “canonical form” [21] (an ordered representation for phylogenetic trees). To enumerate every canonical representation once, we define a parentchild relationship over the space of all ASTs. This induces an enumeration tree over the solution space, where each node represents a collection of ASTs grouped together via an equivalence relation. Leaf nodes represent potential MXSTs and each MXST belongs to a unique leaf node. This scheme is motivated by the reverse search technique for enumeration [34].
Canonical form
The virtual label of an internal node v is the minimum label among all leaf descendants of v. Consider a lefttoright order on the children of an internal node based on the sequence in which they are encountered in an inorder depthfirst traversal (IDFT), the leftmost child being encountered first. Then, a tree T is in canonical form[21] if, for every internal node, its children are ordered from left to right by their virtual labels. It can be seen that two trees are isomorphic if and only if they have the same canonical forms. By generating all trees in canonical form, it is straightforward to test if two trees are isomorphic and prevent duplicate enumeration. MFSTMINER relies on this property to ensure that each FST is enumerated exactly once. Henceforth, we assume all trees to be in canonical form unless mentioned otherwise.
Enumeration tree
An equivalence class is a set E of canonical trees that share a common prefix. We call this common prefix tree the core tree of E and denote it by E^{ c }. Note that an equivalence class of kleaf trees has a (k−1)leaf core tree. For an AST T, ${\mathcal{E}}_{T}$ denotes the equivalence class that has T as its core tree. Any two trees in an equivalence class differ only with respect to their rightmost leaf; therefore, topologically, their difference is restricted to their heaviest subtrees. The equivalence relation “sharing a common prefix” partitions any set of canonical trees into disjoint subsets. Each such subset is an equivalence class identified by its unique core tree.
A node in the enumeration tree is a leaf if its core tree is not a prefix to any other AST. Thus, its corresponding equivalence class is empty. Note that every MXST is the core tree of some leaf node. The converse is not true, because a (k−1)leaf tree may not be the prefix of a given kleaf tree, yet can be a subtree of it. The root of the enumeration tree is an empty node that has all the equivalence classes containing 3leaf ASTs as its children. This is because three is the minimum number of leaves on which phylogenetic inference can be meaningful. For an equivalence class E, the branch at E represents the subtree induced in the enumeration tree by all the leaf descendants of E, or simply E if it is a leaf. ASTs X and Y are considered to be of a common descent if neither is a descendant of the other.
Pairwise join
Our scheme exploits condition (1) heavily. Consider equivalence classes E and F, where E is the parent of F and E consists of (k−1)leaf ASTs. We claim that any kleaf tree T∈F is the result of joining two (k−1)leaf trees in E. Specifically, T is the result of joining a unique ordered pair of trees (T_{ x },T_{ y }) in E such that condition (1) is satisfied. Observe that for any ordered pair (T_{ x },T_{ y }) satisfying condition (1) with respect to T, T_{ x } is the core tree of F and belongs to E. Further, T_{ x } and T_{ y } share a common prefix; thus, T_{ y } also belongs to E. The claim follows.
While every tree in F can be obtained by joining a unique ordered pair (T_{ x },T_{ y }) of trees in E, there may be multiple T s satisfying condition (1) with respect to ordered pair (T_{ x },T_{ y }). The way in which (T_{ x },T_{ y }) join to produce T depends on the topology of the subtree displayed by an input tree over the leaf set ${\mathcal{\mathcal{L}}}_{{T}_{x}}\cup {\mathcal{\mathcal{L}}}_{{T}_{y}}$. We next describe the four possible ways in which an ordered pair (T_{ x },T_{ y }) can join as per condition (1). In the subsequent discussion, let x and y denote the rightmost leaf of T_{ x } and T_{ y } respectively, and, p_{ x } and p_{ y } denote the parents of x and y respectively. Recall that E^{ c } represents the core tree of equivalence class E. Note that E^{ c } is also the common prefix of T_{ x } and T_{ y }. Let r denote the rightmost leaf of E^{ c }. For an internal node u, let numChild(u) denote its number of children. The rightmost path of a tree is the path from the root to its rightmost leaf. There are three possibilities for relative values of ${\text{depth}}^{{T}_{y}}\left({p}_{y}\right)$ and ${\text{depth}}^{{T}_{x}}\left({p}_{x}\right)$ giving rise to different types of joins.
If ${\text{depth}}^{{T}_{y}}\left({p}_{y}\right)={\text{depth}}^{{T}_{x}}\left({p}_{x}\right)$, the following three types of joins are possible.
Example: Figure 7(d) shows the input trees and Figure 7(e) shows the corresponding joined tree.
Type 2: The input trees have the same structure as in a type 1 join (Figure 7(a)); however, in the joined tree x and y are attached to the same parent at one level deeper than their respective depths in the participating trees. See Figure 7(c).
Example: Figure 7(d) shows the input trees and Figure 7(f) shows the corresponding joined tree.
Type 3: Figure 7(g) shows the participating trees. Note that the participating trees are a special case of type 1 and 2 join; i.e., ${\text{depth}}^{{T}_{y}}\left({p}_{y}\right)={\text{depth}}^{{T}_{x}}\left({p}_{x}\right)$ holds here as well. However, in the resulting join p_{ y } becomes the parent of p_{ x } as shown in Figure 7(h). For this to be possible, we must have numChild(p_{ y })=2 in T_{ y }.
Example: Figure 7(k) shows the input trees and Figure 7(l) shows the corresponding joined tree. If ${\text{depth}}^{{T}_{y}}\left({p}_{y}\right)<{\text{depth}}^{{T}_{x}}\left({p}_{x}\right)$, the following join type arises.
Type 4: Figure 7(i) shows the participating trees. Here ${\text{depth}}^{{T}_{y}}\left({p}_{y}\right)<{\text{depth}}^{{T}_{x}}\left({p}_{x}\right)$; i.e., on the rightmost path of E^{ c }, leaf y is attached at a lesser depth than leaf x. As a result there is only one way to join T_{ x } and T_{ y } so as to satisfy condition (1). See Figure 7(j). Here, p_{ y } becomes an ancestor of p_{ x } in the joined tree.
Example: Figure 7(m) shows the input trees and Figure 7(n) shows the corresponding joined tree.
Finally, note that if ${\text{depth}}^{{T}_{y}}\left({p}_{y}\right)>{\text{depth}}^{{T}_{x}}\left({p}_{x}\right)$, no joins are possible: T_{ x } and T_{ y } cannot be joined while satisfying condition (1), because T_{ x } cannot be the prefix of the joined tree. ASTs from such joins are enumerated when considering the ordered pair (T_{ y },T_{ x }).
The above scheme leads to a natural formulation for generating all members of children of E. For every ordered pair (T_{ x },T_{ y })∈E such that the pair joins only in one way in all the trees in the input collection, add the joined tree to ${\mathcal{E}}_{{T}_{x}}$. The ordering indicates that the joined tree has the first tree of the ordered pair as its prefix.
Support estimation
An AST is enumerated by combining two smaller ASTs. However, an AST can arise out of their combination only if the two ASTs exhibit a common type of join (topology) in all the input trees. Determining this involves identifying the types of joins the smaller ASTs exhibit across the input trees, and if a particular join is supported by all the input trees. For this we deploy a onetime least common ancestor based preprocessing step, after which the join type in each input tree can be identified in constant time.
Consider an ordered pair of trees (T_{ x },T_{ y }) in an equivalence class E and let ${\mathcal{\mathcal{L}}}^{\cup}={\mathcal{\mathcal{L}}}_{{T}_{x}}\cup {\mathcal{\mathcal{L}}}_{{T}_{y}}$. For an input tree T, we say the join induced by (T_{ x },T_{ y }) in T is of type A if $T{}_{{\mathcal{\mathcal{L}}}^{\cup}}$ in canonical form corresponds to a type A join with respect to ordered pair (T_{ x },T_{ y }). Let T^{ j o i n } denote $T{}_{{\mathcal{\mathcal{L}}}^{\cup}}$ in canonical form. This step classifies T^{ j o i n } as one of the four join types. If a particular join is supported by all the input trees (i.e. f=1), the corresponding joined tree is an AST. A natural way to classify the join type could be to restrict T to ${\mathcal{\mathcal{L}}}^{\cup}$, canonicalize the restriction and identify the canonicalized tree as one of the four join types. This can be done in time linear in the size of T using the algorithm given in reference [35]. Theorem 1, stated next, improves on this by giving a least common ancestor (LCA) based scheme that in constant time identifies T^{ j o i n } as a result of one of the four join types. The LCA values are computed as a preprocessing step. The meaning of the symbols x,y,p_{ x }and p_{ y } is the same as in Section “Pairwise join” on page 5. Let r denote the rightmost leaf of core tree of E. Superscripts indicate the reference tree.
Theorem 1.
 1.T ^{ j o i n } is a result of a type1 join on ordered pair(T _{ x },T _{ y }) if and only if
 (a)
depth(LCA ^{ T }(r,x))=depth(LCA ^{ T }(r,y)),
 (b)
depth(LCA ^{ T }(r,x))=depth(LCA ^{ T }(x,y)) and
 (c)
ψ(x)<ψ(y).
 (a)
 2.T ^{ j o i n } is a result of a type2 join on ordered pair (T _{ x },T _{ y }) if and only if
 (a)
depth(LCA ^{ T }(r,x))=depth(LCA ^{ T }(r,y)),
 (b)
depth(LCA ^{ T }(r,x))<depth(LCA ^{ T }(x,y)) and
 (c)
ψ(x)<ψ(y).
 (a)
 3.T ^{ j o i n } is a result of a type3 join on ordered pair (T _{ x },T _{ y }) if and only if
 (a)
${\text{depth}}^{{T}_{x}}\left({p}_{x}\right)={\mathit{\text{depth}}}^{{T}_{y}}\left({p}_{y}\right)$ and
 (b)
depth(LCA ^{ T }(r,x))>depth(LCA ^{ T }(r,y)).
 (a)
 4.
T ^{ j o i n } is a result of a type4 join on ordered pair (T _{ x },T _{ y }) if and only if ${\mathit{\text{depth}}}^{{T}_{x}}\left({p}_{x}\right)>{\mathit{\text{depth}}}^{{T}_{y}}\left({p}_{y}\right)$.
Proof.
 1.
Clearly if T ^{ j o i n } is a result of a type1 join, it satisfies 11a11c. To prove the only if part, let 11a11c be satisfied. Since T _{ x } and T _{ y } are obtained by attaching x and y respectively to the rightmost path of E ^{ c }, and each is a subtree of T, 11a implies that depth(p _{ y })=depth(p _{ x }). Thus, T ^{ j o i n } is a result of either a type 1, 2 or 3 join. A type3 join requires p _{ y } to be the parent of p _{ x } in T ^{ j o i n }, which is ruled out by 11a. Further, 11b and 11c imply that the join must be of type 1.
 2.
The proof is similar to that of part 1. Again, T ^{ j o i n } can be a result of either a type1 or 2 join. Conditions 22b and 22c imply that the join must be of type 2.
 3.
Condition 33a implies that T ^{ j o i n } must be a result of a type1, 2 or 3 join. Condition 33b rules out joins of type 1 and 2. Thus the join must be of type 3.
 4.
Follows from the definition of a type4 join.
Cases 1– 4 are mutually exclusive and each can be evaluated in constant time as follows.
We first preprocess the input trees to answer each LCAbased query in Theorem 1 in constant time (see Section “Complexity analysis” on page 13 for more details). Using this, instead of identifying the join type in all the trees in the input collection individually, we do it in constant time across all the input trees at once. That is, in the case of ASTs, for any given ordered pair (T_{ x },T_{ y }) we answer in constant time if a join of the pair results in an AST.
Containing the combinatorial explosion
Although, in principle, we could enumerate all MXSTs by traversing the complete enumeration tree of ASTs, the sheer number of ASTs makes this approach, used by itself, impractical. To mitigate the impact of combinatorial explosion, we use a heuristic that, given a node in the enumeration tree, determines, without traversing the subtree below the node, whether any of its leaf descendants contains a MXST. If none of them does, we prune the branch at the node.
Pruning heuristic
Let X and Y be two equivalence classes. We say that X prunes the branch of the enumeration tree at Y, or simply that X prunes Y, if X and Y are of a common descent, and for every descendant A of Y (including Y), there exists at least one descendant B of X (which can be X itself) such that B^{ c } displays A^{ c }. If X prunes Y, none of the leaf descendants of Y can be an MXST. Thus, the branch at Y need not be enumerated. For example, in Figure 6, node A prunes node G because G has 3 descendants —itself, H and I—, whose respective core trees are displayed by the respective core trees of nodes B, C and D, which are descendants of A. If this information is known when G is first visited, the branch at G can be pruned. Similarly, A also prunes J because the respective core trees of nodes J, K and L are displayed by the respective core trees of nodes B, C and D. Further, among the descendants of A, nodes E and F are respectively pruned by nodes C and D.
For the next set of results, let E denote an equivalence class with r as the rightmost leaf of its core tree. Let X,Y,Z be children of E in the enumeration tree. Let x,y,z be the rightmost leaves of X^{ c },Y^{ c },Z^{ c } respectively. Clearly {X^{ c },Y^{ c },Z^{ c }}∈E. We say [ i,j,k] is an agreement triplet if all the input trees display the same topology over the leaf set {i,j,k}. For an ordered pair of trees (A,B) in an equivalence class, having a and b as their respective rightmost leaves, we say tree T_{ a b }exists if (A,B) join as T_{ a b } across all the input trees. Let I, J and K be three trees belonging to a common equivalence class; let i, j and k be their respective rightmost leaves. Suppose that T_{ i j } and T_{ i k } exist. If the ordered pair (T_{ i j },T_{ i k }) exhibits a common join across all the input trees, we denote the join as T_{i−j k}. Theorem 2 characterizes pruning among “siblings” and “first cousins” in the enumeration tree.
Theorem 2
 1.X prunes Y if either of the following holds:
 (a)
T _{ x y } exists and is not of join type 2.
 (b)
T _{ x y } exists as a join of type 2 and for every child Z of E such that T _{ y z } exists, [x,y,z] is an agreement triplet.
 (a)
 2.
If T _{ x y } and T _{ y z } exist, and T _{ x y } is of join type 2, then ${\mathcal{E}}_{{T}_{\mathit{\text{xy}}}}$ prunes ${\mathcal{E}}_{{T}_{\mathit{\text{yz}}}}$ if T _{ y z } is not of join type 2.
Part 1 of Theorem 2 deals with pruning among siblings; part 2 deals with pruning among first cousins. The proof of Theorem 2 relies on Lemmas 1, 2, 3 and 4, which we present next.
Lemma 1.
 1.If T _{ x y } is not a result of a type2 join:
 (a)
T _{ x z } exists and is not a result of a type2 join.
 (b)
There exists an AST T on leaf set ${\mathcal{L}}_{{E}^{c}}\cup \{x,y,z\}$ and ${\mathcal{E}}_{T}$ is a descendant of X.
 (a)
 2.If both T_{ x y } and T_{ y z } are results of join type 2, and [x,y,z] is an agreement triplet:
 (a)
T _{ x z } exists.
 (b)
There exists an AST T on leaf set ${\mathcal{L}}_{{E}^{c}}\cup \{x,y,z\}$ and ${\mathcal{E}}_{T}$ is a descendant of X.
 (a)
 3.If T _{ x y } is a result of a type2 join and T _{ y } _{ z } is not a result of a type2 join:
 (a)
T _{ x z } exists and is not a result of a type2 join.
 (b)
There exists an AST T on leaf set ${\mathcal{L}}_{{E}^{c}}\cup \{x,y,z\}$ and ${\mathcal{E}}_{T}$ is a descendant of ${\mathcal{E}}_{{T}_{\mathit{\text{xy}}}}$, i.e., T_{x yz} exists.
 (a)
Lemma 1 gives conditions under which for a given child ${\mathcal{E}}_{{T}_{\mathit{\text{yx}}}}$ of Y, X has a descendant (specifically a grandchild) whose core tree displays T_{ y x }. Intuitively, this is an intermediate step in proving conditions under which X either prunes Y or ${\mathcal{E}}_{{T}_{\mathit{\text{yx}}}}$. The specific results of Lemma 1 help in cascading the effect to further descendants of Y or ${\mathcal{E}}_{{T}_{\mathit{\text{yx}}}}$. Each T_{ x y } and T_{ y z } can be a result of one of the four types of join. Thus, considering T_{ x y } and T_{ y z } together, there are 16 possibilities. Out of these, the case where each T_{ x y } and T_{ y z } is result of a type2 join is the only case where there can be multiple topologies that display both T_{ x y } and T_{ y z }. That is why type2 joins have a special significance in Lemma 1. The remaining 15 cases guarantee the existence of a single topology that displays both T_{ x y } and T_{ y z }.
Lemma 2.
If T_{ x y } and T_{ x z } exist, and [ x,y,z] is an agreement triplet, either T_{x−y z} or T_{x−z y} exists.
Lemma 2 states that for any two children of X with y and z as the rightmost leaves of their respective core trees, the existence of agreement triplet [ x,y,z] is a sufficient condition for the children to join in one of the two possible ways. That is, there exists only one topology that displays both the children; further, the topology must be a descendant of X.
Lemma 3.
Suppose A and B are two ASTs with a and b as their respective rightmost leaves such that ${\mathcal{\mathcal{L}}}_{A}\subset {\mathcal{\mathcal{L}}}_{B}$. Then, ${\mathcal{E}}_{B}$ is a descendant of ${\mathcal{E}}_{A}$ if and only if for every $\ell \in \{{\mathcal{\mathcal{L}}}_{B}\setminus {\mathcal{\mathcal{L}}}_{A}\}$, T_{ a ℓ } exists.
Lemma 4.
Suppose T_{ x y } exists as a result of a type2 join and D is descendant of Y. Then, for any $\{a,b\}\in \{{\mathcal{\mathcal{L}}}_{{D}^{c}}\setminus {\mathcal{\mathcal{L}}}_{{Y}^{c}}\}$, [ x,a,b] is an agreement triplet if [ x,y,a] and [x,y,b] are agreement triplets.
Lemma 4 deals with the special case of type2 joins for T_{ x y }. Intuitively, it states that for any two children of Y with a and b as the rightmost leaves of their respective core trees, agreement triplets [ x,y,a] and [ x,y,b] together form a sufficient condition for the existence of a descendant of X whose core tree displays the core trees of both children of Y. This is a stepping stone in proving that for every descendant D of Y, there exists a descendant of X whose core tree displays the core tree of D, thus, X prunes Y.
The proofs of the above Lemmas are given in Appendix: Proofs. We present next the proof of Theorem 2. In the proof, and in the rest of the paper, we represent trees in parenthesized Newick format (http://evolution.genetics.washington.edu/phylip/newicktree.html). E.g., (a,(b,c)) represents the tree with leaf set {a,b,c} where the LCA of b and c is a proper descendant of the LCA of a, b and c, and (a,b,c) represents unresolved (star) tree on {a,b,c}.
Proof of Theorem 2
 (a)Consider any descendant S of Y. Consider any $\{a,b\}\in \{{\mathcal{\mathcal{L}}}_{{S}^{c}}\setminus {\mathcal{\mathcal{L}}}_{{Y}^{c}}\}$. Since S is a descendant of Y, T _{ y a }∈Y and T _{ y b }∈Y exist as per Lemma 3. Further, since T _{ x y } is not of join type 2, as per Lemma 1.1: (i) T _{ x a }∈X and T _{ x b }∈X exist, and each is also not a result of a type 2join, and (ii) there exists ASTs on leaf sets ${\mathcal{\mathcal{L}}}_{{E}^{c}}\cup \{x,y,a\}$ and ${\mathcal{\mathcal{L}}}_{{E}^{c}}\cup \{x,y,b\}$, thus, [ x,y,a] and [ x,y,b] are agreement triplets. Let A and B denote the children of E with a and b as their respective rightmost leaves. Since AST S exists, there exists an AST on leaf set ${\mathcal{\mathcal{L}}}_{{E}^{c}}\cup \{a,b\}$, i.e., either T _{ a b }∈A or T _{ b a }∈B exists. Without loss of generality, let T _{ a b } exist. Since, T _{ x a } exists and is not a result of a type2 join, and T _{ a b } exists, as per Lemma 1.1, there exists an AST on leaf set ${\mathcal{\mathcal{L}}}_{{E}^{c}}\cup \{x,a,b\}$. Thus:

for every leaf $\ell \in \{{\mathcal{\mathcal{L}}}_{{S}^{c}}\setminus {\mathcal{\mathcal{L}}}_{{X}^{c}}\}$, T_{ x ℓ } exists, thus, for every pair of leaves {x_{1},x_{2}} in X^{ c }, [ x_{1},x_{2},ℓ] is an agreement triplet.

for every pair of leaves $\{a,b\}\in \{{\mathcal{\mathcal{L}}}_{{S}^{c}}\setminus {\mathcal{\mathcal{L}}}_{{X}^{c}}\}$, there exists an AST on leaf set ${\mathcal{\mathcal{L}}}_{{E}^{c}}\cup \{x,a,b\}$, thus, for every leaf ℓ in X^{ c }, [ ℓ,a,b] is an agreement triplet.
Thus, there exists an AST T on leaf set ${\mathcal{\mathcal{L}}}_{{S}^{c}}\cup {\mathcal{\mathcal{L}}}_{{X}^{c}}$. Clearly T displays S^{ c }. Further, for every $\ell \in \{{\mathcal{\mathcal{L}}}_{{S}^{c}}\setminus {\mathcal{\mathcal{L}}}_{{X}^{c}}\}$, T_{ x ℓ } exists. Thus, by Lemma 3, T is descendant of X. Hence, X prunes Y, as claimed.

 (b)Consider any descendant S of Y. Consider any $\{a,b\}\in \{{\mathcal{\mathcal{L}}}_{{S}^{c}}\setminus {\mathcal{\mathcal{L}}}_{{Y}^{c}}\}$. Since, S is a descendant of Y, by Lemma 3, T_{ y a } and T_{ y b } exists. Thus, as per the if condition of the claim to be proved, [ x,y,a] and [ x,y,b] are agreement triplets. Since T_{ x y } exists as a result of type2 join and, [ x,y,a] and [ x,y,b] are agreement triplets, by Lemma 4, [ x,a,b] is an agreement triplet, and, by Lemma 1 (part 2 and 3), T_{ x a } and T_{ x b } exist. Thus, as per Lemma 2, there exists an AST on leaf set ${\mathcal{\mathcal{L}}}_{{E}^{c}}\cup \{x,a,b\}$. Thus:

for every leaf $\ell \in \{{\mathcal{\mathcal{L}}}_{{S}^{c}}\setminus {\mathcal{\mathcal{L}}}_{{X}^{c}}\}$, T_{ x ℓ } exists, thus, for every pair of leaves {x_{1},x_{2}} in X^{ c }, [ x_{1},x_{2},ℓ] is an agreement triplet.

for every pair of leaves $\{a,b\}\in \{{\mathcal{\mathcal{L}}}_{{S}^{c}}\setminus {\mathcal{\mathcal{L}}}_{{X}^{c}}\}$and for every leaf ℓ in X^{ c }, there exists and AST on leaf set ${\mathcal{\mathcal{L}}}_{{E}^{c}}\cup \{x,a,b\}$, thus, [ℓ,a,b] is an agreement triplet.
Thus, there exists an AST T on leaf set ${\mathcal{\mathcal{L}}}_{{S}^{c}}\cup {\mathcal{\mathcal{L}}}_{{X}^{c}}$. Clearly T displays S^{ c }. Further, for every $\ell \in \{{\mathcal{\mathcal{L}}}_{{S}^{c}}\setminus {\mathcal{\mathcal{L}}}_{{X}^{c}}\}$, T_{ x ℓ } exists, thus, by Lemma 3, T is descendant of X. Hence, X prunes Y, as claimed.

 2.Since T _{ y z } is not a result of a type2 join, by Lemma 1.3, T _{ x z } exists and is not a result of a type2 join, and T _{x y−z} exists. Consider any descendant S of ${\mathcal{E}}_{{T}_{\mathit{\text{yz}}}}$. Consider any $\ell \in \{{\mathcal{\mathcal{L}}}_{{S}^{c}}\setminus {\mathcal{\mathcal{L}}}_{{T}_{\mathit{\text{yz}}}}\}$. Since S is a descendant of Y, by Lemma 3, T _{ y ℓ } exists. We show that T _{ y ℓ } is not a result of a type2 join by contradiction. Let T _{ y ℓ } be a result of a type2 join with triplet [r,y,ℓ] of type (r,(y,ℓ)). Since S is a descendant of ${\mathcal{E}}_{{T}_{\mathit{\text{yz}}}}$, by Lemma 3, the join ${T}_{y\mathrm{z\ell}}\in {\mathcal{E}}_{{T}_{\mathit{\text{yz}}}}$ on ordered pair (T _{ y z },T _{ y ℓ }) exists. Let T _{ y z } be of type 1 join with triplet [ r,y,z] of type (r,y,z). Since T _{y−z ℓ} displays both (r,(y,ℓ)) and (r,y,z), it must also display (r,(y,ℓ),z). However, (r,(y,ℓ),z) cannot exist in T _{y−z ℓ} because ℓ and z cannot be the last and secondtolast leaves respectively in the IDFT. Similarly, for T _{ y z } of join type 3 or type 4, we can show that ℓ cannot be the rightmost leaf in T _{y−z ℓ}. Thus, T _{ y ℓ } is not of join type 2. Thus, by Lemma 1.3, T _{ x ℓ } exists and is not a result of type 2 join, and T _{x y−ℓ} exists. Consider any $\{a,b\}\in \{{\mathcal{\mathcal{L}}}_{{S}^{c}}\setminus {\mathcal{\mathcal{L}}}_{{T}_{\mathit{\text{xy}}}}\}$. Thus, both T _{ x a } and T _{ x b } exist and each is not a result of join type 2. Let A and B denote the ASTs in E with a and b as their rightmost leaves. Without loss of generality, let the AST on leaf set ${\mathcal{\mathcal{L}}}_{{E}^{c}}\cup \{a,b\}$ be a result of a join on the order pair (A ^{ c },B ^{ c }), i.e., T _{ a b } exists. Thus, by Lemma 1.1, there exists an AST on leaf set ${\mathcal{\mathcal{L}}}_{{E}^{c}}\cup \{x,a,b\}$. Thus:

for every $\ell \in \{{\mathcal{\mathcal{L}}}_{{S}^{c}}\setminus {\mathcal{\mathcal{L}}}_{{T}_{\mathit{\text{xy}}}}\}$, T_{x y−ℓ} exists, thus, for every pair of leaves {x_{1},x_{2}} in T_{ x y }, [ x_{1},x_{2},ℓ] is an agreement triplet.

for every $\{a,b\}\in \{{\mathcal{\mathcal{L}}}_{{S}^{c}}\setminus {\mathcal{\mathcal{L}}}_{{T}_{\mathit{\text{xy}}}}\}$ and for every leaf ℓ in T_{ x y }, there exists an AST on leaf set ${\mathcal{\mathcal{L}}}_{{E}^{c}}\cup \{x,a,b\}$, thus, [ ℓ,a,b] is an agreement triplet.
Thus, there exists an AST T on leaf set ${\mathcal{\mathcal{L}}}_{{S}^{c}}\cup {\mathcal{\mathcal{L}}}_{{T}_{\mathit{\text{xy}}}}$. Clearly T displays S^{ c }. Further, since for every $\ell \in \{{\mathcal{\mathcal{L}}}_{{S}^{c}}\setminus {\mathcal{\mathcal{L}}}_{{T}_{\mathit{\text{xy}}}}\}$, T_{x y−ℓ} exists, by Lemma 3, T is descendant of ${\mathcal{E}}_{{T}_{\mathit{\text{xy}}}}$. Hence, ${\mathcal{E}}_{{T}_{\mathit{\text{xy}}}}$ prunes ${\mathcal{E}}_{{T}_{\mathit{\text{xz}}}}$, as claimed.

□
Prunerlist
Note that conditions in part (1a) and part (2) of Theorem 2 can be evaluated in constant time while testing the condition in part (1b) of Theorem 2 takes time linear in the size of the tree being pruned. Neither of these require enumerating the pruned branch at Y. However, there are cases when Y or a descendant of Y is pruned by X but it cannot be identified using Theorem 2. In this case, the branch at Y must be enumerated and potential pruning by X verified. For this, we maintain a “prunerlist” for every child of Y. We explain this idea next.
Now, using arguments similar to the proof of Theorem 2, we can show that:
Theorem 3
 1.
Y has no children and has a in its prunerlist.
 2.
All children of Y have a in their prunerlist.
MFSTMINER
In line 17, ENUMERATENODE calls itself recursively to enumerate the children of a nonempty equivalence class ${\mathcal{E}}_{{T}_{x}}$, provided ${\mathcal{E}}_{{T}_{x}}$ is found to be not pruned.
The general case of enumerating MFSTs
We now explain how MFSTMINER handles the general case of mining MFSTs. The main difference between mining for MXSTs and mining for MFSTs is that the former is (as we have seen) based on enumerating ASTs, while the latter is based on enumerating FSTs. While an ASTs must be supported by all the input trees (i.e., f=1), an FSTs need only be supported by some fraction $f\in \left(\frac{1}{2},1\right)$ of the input trees. This difference affects neither the enumeration tree nor the pairwise join, but it does affect support estimation and the pruning strategy. We discuss these steps next.
Support estimation
Given T_{ x } and T_{ y } in an equivalence class, a join T_{ x y } on ordered pair (T_{ x },T_{ y }) is an FST if it is supported by at least a fraction f of the input trees (i.e., if at least a fraction f of the input trees have T_{ x y } as a subtree). Note that any such T_{ x y } is supported only by those trees that support both T_{ x } and T_{ y } as well. Motivated by this, for each FST T_{ x } we maintain a support list, denoted by T_{ x }.supList, that contains all trees in the input collection that support T_{ x }. To estimate if the join on (T_{ x },T_{ y }) results in an FST, we apply Theorem 1 only on trees in T_{ x }.supList∩T_{ y }.supList. We store the support list as a bitmap [36] for efficient memory utilization and fast computation of intersection of support lists.
Pruning strategy
To verify whether an equivalence class X prunes an equivalence class Y, we also need to consider the support lists of X^{ c } and Y^{ c }. We say [ x,y,z] is a frequent triplet if at least fraction f of the input trees display the same triplet over the leaf set {x,y,z}. Let [ x,y,z].supList denote the support list of such a frequent triplet. Based on this, we can restate Theorem 2 for the case of enumerating MFSTs as follows.
Theorem 4
 1.X prunes Y if either
 (a)
T _{ x y } exists, Y ^{ c }.supList⊆X ^{ c }.supList and T _{ x y } is not of join type 2, or
 (b)
T _{ x y } exists as a type2 join, Y ^{ c }.supList⊆X ^{ c }.supList and for every Z∈E such that T _{ y z } exists, [ x,y,z] is a frequent triplet with Y ^{ c }.supList⊆[ x,y,z].supList.
 (a)
 2.
If T _{ x y } and T _{ y z }, exist and T _{ x y } is of join type 2, then ${\mathcal{E}}_{{T}_{\mathit{\text{xy}}}}$ prunes ${\mathcal{E}}_{{T}_{\mathit{\text{yz}}}}$ if T _{ y z } is not of join type 2 and T _{ y z }.supList⊆T _{ x y }.supList.
Prunerlist
 1.
${\mathcal{E}}_{{T}_{\mathit{\text{yz}}}}.\text{prunerList}$ contains the entry (x,T _{ x y }.supList) if T _{ x y } is not of join type 2 and T _{ x y }.supList∩T _{ y z }.supList≥f.
 2.
${\mathcal{E}}_{{T}_{\mathit{\text{yz}}}}.\text{prunerList}$ contains the entry (x,S _{∩}=T _{ x y }.supList∩[ x,y,z].supList) if T _{ x y } is of join type 2, [ x,y,z] is a frequent triplet and S _{∩}∩T _{ y z }.supList≥f.
 3.
For every leaf label w such that $(w,{S}_{\cap}^{y})\in {\mathcal{E}}_{{T}_{y}}.\text{prunerList}$ and $(w,{S}_{\cap}^{z})\in {\mathcal{E}}_{{T}_{z}}.\text{prunerList}$ exist, ${\mathcal{E}}_{{T}_{\mathit{\text{yz}}}}.\text{prunerList}$ contains entry $(w,{S}_{\cap}={S}_{\cap}^{y}\cap {S}_{\cap}^{z})$ if S _{∩}∩T _{ y z }.supList≥f.
Condition 1 and 2 describe addition of new labels to the prunerlist of ${\mathcal{E}}_{{T}_{\mathit{\text{yz}}}}$, while condition 3 describes inheritance of labels from the intersection of the prunerlists of ${\mathcal{E}}_{{T}_{y}}$ and ${\mathcal{E}}_{{T}_{z}}$. Now, the corresponding result for Theorem 3 can be stated as:
Theorem 5
 1.
${\mathcal{E}}_{{T}_{\mathit{\text{yz}}}}$ is pruned by A if (i) for every ${T}_{\mathit{\text{yb}}}\in {\mathcal{E}}_{{T}_{y}}$, ${\mathcal{E}}_{{T}_{\mathit{\text{yb}}}}.\text{prunerList}$ contains an entry (a,S _{ b }(a)), and (ii) for ${S}_{\cap}=\bigcap _{{T}_{\mathit{\text{yb}}}\in {\mathcal{E}}_{{T}_{y}}}{S}_{b}\left(a\right)$, ${\mathcal{E}}_{{T}_{\mathit{\text{yz}}}}.\text{supList}={S}_{\cap}$.
 2.
${\mathcal{E}}_{{T}_{y}}$ is pruned by A if (i) ${\mathcal{E}}_{{T}_{y}}$ is empty and has a in its pruner list, or (ii) every child ${\mathcal{E}}_{{T}_{\mathit{\text{yb}}}}$ of ${\mathcal{E}}_{{T}_{y}}$ is pruned by A as per part 1 of this Theorem.
This completes the description of MFSTMINER for the general case of mining MFSTs. The overall framework is the same as the special case of mining all MXSTs. The difference lies in the finer details of incorporating support lists in the support estimation and the pruning step. These details were discussed in this section and are easy to incorporate in Algorithms 1 and 2.
Complexity analysis
Here we discuss the runtime complexity of the preprocessing step, the data structures used in the algorithm implementation and the memory requirements in each step of MFSTMINER algorithm. In the following discussion, let the input collection consist of n trees on a common leaf set and let f denote the input fraction for computing ffrequent subtrees.
Preprocessing
This onetime task involves (1) computing LCA mappings for all pairs of leaves for all the input trees and (2) enumerating all frequent triplets. For each tree T in the input collection, and every pair {u,v} of leaves of T, step (1) computes LCA^{ T }(u,v) and stores it in a threedimensional array indexed by triplet (T,u,v), thus, requires $O\left(n\right\mathcal{\mathcal{L}}{}^{2})$ space. In our implementation, these LCA values are computed in quadratic time and space per tree by traversing the tree in a depthfirst manner and computing the LCA values of the leafdescendants at a node. Thus, for all the input trees, Step 1 takes $O\left(n\right\mathcal{\mathcal{L}}{}^{2})$ time and space. In the case of MXSTs only a twodimensional array is used (requiring $O\left(\right\mathcal{\mathcal{L}}{}^{2})$ space) to store the LCA values because an LCA value is relevant only if it is the same across all input trees, i.e., f=1. We should point out that it is wellknown that one can preprocess a tree in linear time and space to produce a data structure that can answer any LCA query on that tree in constant time [37–39]. Such algorithms are quite useful when the number of LCA queries is limited and the preprocessing dominates the total time. That is not the case in our application. Indeed, MFSTMINER queries all possible LCA values while enumerating all MFSTs on three leaves, and then does a constant number of LCA queries for every join operation thereafter. Although both our threedimensional array and the specialized LCA data structures [37–39] offer constanttime access to LCAvalues, the former’s constant factor is smaller than the latter’s, which makes a significant difference in practice.
Step 2 takes $O\left(n\right\mathcal{\mathcal{L}}{}^{3})$ time and space, and uses the precomputed LCA values from step (1). In the case of MXSTs, just as storing of LCA values requires less space ($O\left(\right\mathcal{\mathcal{L}}{}^{2})$), the complexity in step (2) is also reduced: $O\left(\right\mathcal{\mathcal{L}}{}^{3})$ time and space.
Joinoperation
 1.T ^{ j o i n } is a result of a type1 join on ordered pair (T _{ x },T _{ y }) if and only if
 (a)
the triplet on leaves {r,x,y} is of type (r,x,y) and
 (b)
ψ(x)<ψ(y).
 (a)
 2.T ^{ j o i n } is a result of a type2 join on ordered pair (T _{ x },T _{ y }) if and only if
 (a)
the triplet on leaves {r,x,y} is of type (r,(x,y)) and
 (b)
ψ(x)<ψ(y).
 (a)
 3.T ^{ j o i n } is the result of a type3 join on ordered pair (T _{ x },T _{ y }) if and only if
 (a)
${\text{depth}}^{{T}_{x}}\left({p}_{x}\right)={\text{depth}}^{{T}_{y}}\left({p}_{y}\right)$ and
 (b)
the triplet on leaves {r,x,y} is of type ((r,x),y).
 (a)
 4.T ^{ j o i n } is a result of a type4 join on ordered pair (T _{ x },T _{ y }) if and only if
 (a)
${\text{depth}}^{{T}_{x}}\left({p}_{x}\right)>{\text{depth}}^{{T}_{y}}\left({p}_{y}\right)$ and
 (b)
the triplet on leaves {r,x,y} is of type ((r,x),y).
 (a)
The advantage of reformulating Theorem 1 as above is that (a) for every tree in the input collection, we need not store the depth of its nodes, and (b) for every FST enumerated as a result of a join operation, we only need to store the depth of the parent of its rightmost leaf. Further, the type of tree a certain triplet displays can be easily known through a constant number of queries on precomputed LCA values.
Supportlist and Prunerlist
In the case of MXSTs, there is no supportlist and the prunerlist contains leaf labels. This takes $O\left(\right\mathcal{\mathcal{L}}\left\right)$ space per enumerated AST that is currently in memory. Note that MFSTMINER uses a depthfirst strategy for traversing the enumeration tree. Thus, not all enumerated ASTs are held in memory at any given time. In the case of MFSTs, both supportlist and prunerlist exist. The supportlist for an FST contains the list of input trees that display the FST. This takes O(n/w) space per enumerated AST that is currently in memory, where w is the size of the machine word. The i^{ t h } bit of a supportlist is set to 1 if the corresponding FST is displayed by the i^{ t h } tree in the input collection, and 0 otherwise. Our experiments were run on a w=64 bit processor, which is typically the case with any modern computer. An entry in prunerlist contains a leaflabel and a supportlist. This takes $O\left(\right(n/w)+\mathcal{\mathcal{L}}\left\right)$ space per enumerated AST that is currently in memory. These are worstcase estimates and in practice the memory consumption is much less because prunerlist is required only for cases not captured by Theorems 2 and 4.
The next result shows that the memory required by MFSTMINER scales polynomially with the number of input trees and the size of the common leaf set.
Theorem 6
MFSTMINER requires $O\left(n\right\mathcal{\mathcal{L}}{}^{3})$ space in the case of enumerating MFSTs and $O\left(\right\mathcal{\mathcal{L}}{}^{3})$ space when only MXSTs are being enumerated.
Proof.
The enumeration tree has depth at most $\left\mathcal{\mathcal{L}}\right$. Enumerating an FST at this depth will require storing $O\left(\right\mathcal{\mathcal{L}}\left\right)$ ancestor equivalences classes, each of which can have at most $\left\mathcal{\mathcal{L}}\right$ FSTs. Thus, the maximum number of FSTs to be stored is $O\left(\right\mathcal{\mathcal{L}}{}^{2})$. Storing each such FST requires $O\left(\right\mathcal{\mathcal{L}}\left\right)$ space for the subtree, O(n/w) space for the supportlist and $O\left(\right(n/w)+\mathcal{\mathcal{L}}\left\right)$ space for the prunerlist, where w is the size of the machine word. Thus, the maximum space required to store all FSTs is $O\left(\right((n/w)+\left\mathcal{\mathcal{L}}\right\left)\right\mathcal{\mathcal{L}}{}^{2})$. Adding to this the space required to store LCA mappings, which is $O\left(n\right\mathcal{\mathcal{L}}{}^{3})$, we get the claimed figure. Similarly, it can be shown that in the case of MXSTs, MFSTMINER requires $O\left(\right\mathcal{\mathcal{L}}{}^{3})$ space.
Let $\left\mathcal{F}\right$ be the number of FSTs (not MFSTs) the input collection displays. Then, the worstcase time complexity of MFSTMINER is $O\left(n\right\mathcal{F}+\mathcal{\mathcal{L}}\left\right\mathcal{F}\left\right)$, which is the same as EVOMINER’s [10]. The time complexity is not polynomial in the number of MFSTs, because we cannot polynomially bound the number of FSTs that MFSTMINER will enumerate to verify the pruning of an equivalence class. Indeed, it could happen that X prunes Y, but that this cannot be confirmed by Theorems 2 and 4. If so, MFSTMINER must enumerate the branch at Y further, and there is no polynomial bound on the number of FSTs that would have to be generated to verify the pruning of Y by X.
Nonetheless, as we will see in the next section, even though MFSTMINER shares the same worstcase time complexity with EVOMINER, it can be orders or magnitudes faster than EVOMINER in practice.
Results and discussion
 1.
Comparison of MFSTs with MASTs.
 2.
Comparison of MfstMiner with EvoMiner [10] — the stateoftheart algorithm for enumerating all phylogenetic FSTs.
 3.
Evaluation of the scalability of MfstMiner with respect to the number of trees, the size of the leaf set and the support value.
 4.
Comparison with Ramu et al.’s [23] approach that mines MFSTs having maximum leaves.
Our dataset consists of bootstrapped trees from a previous study [40] on bootstrapping methods. There are seventeen sets of trees constructed from a diverse range of sequences including rbcL genes, mammalian sequences, bacterial and archaeal sequences, ITS sequences, fungal sequences, and grasses. The number of taxa in these singlegene and multigene DNA sequences vary from 1252554. The entire dataset is available at http://lcbb.epfl.ch/BS.tar.bz2. We refer to the seventeen datasets as A–Q in the increasing order of taxa in the DNA sequences from which the trees were constructed. A corresponds to the set of trees with 125 taxa and Q corresponds to the set of trees with 2554 taxa. To extract datasets with different numbers of leaves and trees, we randomly selected the required number of trees and restricted them on a random set of leaves of the required size.
The experiments were split over 4 machines:

Two machines running Windows 7 64bit with processor clockspeed of 3.4 GHz, 4 cores and 8 threads.

One machine running Windows 7 64bit with processor clockspeed of 3.16 GHz and 2 cores.

One machine running Linux 64bit with processor clockspeed of 2.0 GHz, 6 cores and 12 threads.
Each experiment was averaged over 5 runs. For practical purposes, each run was allowed a maximum of 10000 seconds. Thus, any missing entry in the graphs indicate that the corresponding experiment took more than this limit. Initially, we started with all experiments on one machine and using only one core at a time — the ideal environment — to allow maximum fairness in comparing results, however, we soon realized that this would take more than 600 days of runtime. Thus, we split the experiments using maximum number of cores and threads on each machine. This did slow down things because of competing memory and disk requirements, however, the final runtimes should not be more than a factor of two of the runtimes in the ideal environment.
MFSTs vs. MASTs
Figure 8(b) compares the number of MASTs with the number of MFSTs for f=1. There are significantly more MFSTs. This is notable, because any MFST that is not a MAST is also not displayed by any of the MASTs. Thus, such a MFST reveals unique agreement information among the input trees. This experiment was conducted on a set of 100 trees on 100 leaves from each of the datasets.
Comparison with EVOMINER.
Scalability of MFSTMINER
We evaluated the scalability of MFSTMINER with respect to the number of leaves (10250), the number of trees (10010000) and the support value (.511.0) on datasets having at least 250 leaves, i.e., datasets D (354 taxa) — Q (2554 taxa). Presenting results for all datasets would have been overwhelming, thus, we discuss results for datasets D (354 taxa), K (1481 taxa) and Q (2554 taxa) — the first, the last and a middle one from datasets DQ.
The above results also show that MFSTMINER can handle much larger datasets than EVOMINER. Again, the missing entries are due to the 10000 second time limit. However, if time is not a constraint, as discussed before, the memory requirements of MFSTMINER is polynomial in the size of the input, thus, it can handle large datasets.
Comparison with Ramu et al.’s approach
We compared our approach with Ramu et al.’s [23] heuristic approach that mines MFSTs with maximum leaves. We used the original implementation shared by the authors. The current implementation mines only one MFST with maximum leaves, thus, we cannot compare the number of subtrees mined by our approach with theirs. Further, the current implementation has major portions written in Perl, a highlevel interpreted programming language, and involves significant disk usage for storing intermediate datastructures, whereas, our implementation is written in C++, a much lowerlevel compiled programming language, and keeps all intermediate datastructures in memory. Thus, we did not compare the runtime because our implementation has much advantage with respect to the speed of execution. We compare the size of the MFST with maximum leaves mined by Ramu et al.’s [23] implementation with ours. We did this comparison on a set of 100 trees with 20 leaves from each of the datasets for support values f=.55 and f=.75. In 25 out of 34 cases, the size of the MFST with maximum leaves returned by Ramu et al.’s [23] approach was at least as good as ours. Only in 9 cases it returned an MFST with one leaf less than ours. So, if the goal is to get an MFST with most leaves, Ramu et al.’s [23] approach seems nearperfect. As mentioned in their paper [23], it also seems to be capable of handling large datasets in terms of the number of trees and the number of leaves. However, if the goal is to mine all MFSTs with maximum leaves or simply all MFSTs, then our approach serves better. This can be very useful because there can be a lot of MFSTs (either with maximum leaves or all of them), and every MFST returned by our approach conveys some unique agreement information not conveyed by any of remaining returned MFSTs.
Conclusions
Although we have restricted our attention to enumerating MFSTs for $f\in \left(\frac{1}{2},1\right]$, we can extend MFSTMINER to enumerate all MFSTs for $f\in \left(0,\frac{1}{2}\right]$, with small modifications in the pruning strategy. Note, however, that when $f\in \left(0,\frac{1}{2}\right]$ there can potentially be different MFSTs with the same leaf set.
As a future work, we intend to do a thorough comparison of MFSTs against MASTs, in the settings where MAST is currently used [2, 5, 7]. Since the time to enumerate MFSTs for larger leaf sets can be prohibitive, we also intend to develop schemes to sample at random from the set of all MFSTs.
An intriguing open problem is to devise methods to find common patterns in collections of phylogenetic networks [41–44]. Although techniques from maximal subgraph mining [16, 17] may prove useful here, the special characteristics of phylogenetic networks add interesting twists to the problem. We also intend to extend our work for mining frequent substructures in multilabeled trees [45–48].
The current implementation of MFSTMINER, which works for up to 250 leaves and 10000 trees, is available at https://code.google.com/p/mfstminer/.
Appendix: Proofs
Proof of Lemma 1
 1.Suppose T _{ x y } is a result of a type1 join. Thus, ψ(x)<ψ(y) and agreement triplet [r,x,y] is of type (r,x,y). We have four possibilities to consider.
 (a)
T _{ y z } is a result of a type1 join (see Figure 16(a)). Thus, ψ(y)<ψ(z) and agreement triplet [ r,y,z] is of type (r,y,z). Potential AST T must be obtained by grafting z in T _{ x y }. Since T must display (r,y,z), there is only one possibility of grafting z in T _{ x y }: z should be grafted on the common parent of x and y. Thus, AST T exists. Further, since, ψ(x)<ψ(y)<ψ(z), there is only one possible canonical topology for potential AST T: see Figure 16(a). Since T has x, y, z, as the thirdtolast, secondtolast and last leaf respectively in the IDFT, pruning y will result in a tree that is (a) canonical, (b) has z as the last leaf in the IDFT, and (c) has x as the secondtolast leaf in the IDFT. By definition, the resulting tree is T _{ x z } (see Figure 16(a)). Thus, T _{ x z } exists. Further, the topology of T _{ x z } implies that T _{ x z } is a result of type 1 join. Similarly, pruning the last leaf, i.e., z, in T will result in T _{ x y }. Thus, ${\mathcal{E}}_{T}$ is a a child of ${\mathcal{E}}_{{T}_{\mathit{\text{xy}}}}$, thus, a descendant of X.
 (b)
T _{ y z } is a result of a type2 join (see Figure 16(b)). Thus, ψ(y)<ψ(z) and agreement triplet [ r,y,z] is of type (r,(y,z)). Potential AST T must be obtained by grafting z in T _{ x y }. Since T must display (r,(y,z)), there is only one possibility of grafting z in T _{ x y }: z should be grafted on the edge (p _{ y },y). Thus, AST T exists. Further, since, ψ(x)<ψ(y)<ψ(z), there is only one possible canonical topology for potential AST T; see Figure 16(b). Since T has x, y, z as the thirdtolast, secondtolast and last leaf respectively in the IDFT, pruning y will result in a tree that is (a) canonical, (b) has z as the last leaf in the IDFT, and (c) has x as the secondtolast leaf in the IDFT. By definition, the resulting tree is T _{ x z } (see Figure 16(b)). Thus, T _{ x z } exists. Further, the topology of T _{ x z } implies that T _{ x z } is a result of a type1 join. Similarly, pruning the last leaf, i.e., z, in T will result in T _{ x y }. Thus, ${\mathcal{E}}_{T}$ is a a child of ${\mathcal{E}}_{{T}_{\mathit{\text{xy}}}}$, thus, a descendant of X.
 (c)
T _{ y z } is a result of a type3 join (see Figure 16(c)). Potential AST T must be obtained by grafting x in T _{ y z }. Since T must display (r,x,y), there is only one possibility of grafting x in T _{ y z }: x should be grafted on the parent of y. Thus, AST T exists. Further, since, ψ(x)<ψ(y), there is only one possible canonical topology for potential AST T; see Figure 16(c). Since T has x, y, z as the thirdtolast, secondtolast and last leaf respectively in the IDFT, pruning y will result in a tree that is (a) canonical, (b) has z as the last leaf in the IDFT, and (c) has x as the secondtolast leaf in the IDFT. By definition, the resulting tree is T _{ x z } (see Figure 16(c)). Thus, T _{ x z } exists. Further, the topology of T _{ x z } implies that T _{ x z } is a result of a type3 join. Similarly, pruning the last leaf, i.e., z, in T will result in T _{ x y }. Thus, ${\mathcal{E}}_{T}$ is a a child of ${\mathcal{E}}_{{T}_{\mathit{\text{xy}}}}$, thus, a descendant of X.
 (d)T _{ y z } is a result of a type4 join (see Figure 16(d)). Potential AST T must be obtained by grafting x in T _{ y z }. Since T must display (r,x,y), there is only one possibility of grafting x in T _{ y z }: x should be grafted on the parent of y. Thus, AST T exists. Further, since, ψ(x)<ψ(y), there is only one possible canonical topology for potential AST T; see Figure 16(d). Since T has x, y, z as the thirdtolast, secondtolast and last leaf respectively in the IDFT, pruning y will result in a tree that is (a) canonical, (b) has z as the last leaf in the IDFT, and (c) has x as the secondtolast leaf in the IDFT. By definition, the resulting tree is T _{ x z } (see Figure 16(d)). Thus, T _{ x z } exists. Further, the topology of T _{ x z } implies that T _{ x z } is a result of a type4 join. Similarly, pruning the last leaf (i.e., z) in T will result in T _{ x y }. Thus, ${\mathcal{E}}_{T}$ is a a child of ${\mathcal{E}}_{{T}_{\mathit{\text{xy}}}}$, thus, a descendant of X.
Similarly, one can show that if T_{ x y } is a result of a join of type 3 or 4, irrespective of the type of join T_{ y z } is a result of, ASTs T and T_{ x z } exist, T_{ x z } is not a result of a type2 join, and ${\mathcal{E}}_{T}$ is a descendant of X.
 (a)
 2.Suppose each of T _{ x y } and T _{ y z } is a result of a type2 join (see Figure 17(a)). Thus, agreement triplet [ r,y,z] is of type (r,(y,z)) and ψ(y)<ψ(z). Potential AST T must be obtained by grafting z in T _{ x y }. Since T must display (r,(y,z)) and ψ(x)<ψ(y)<ψ(z), there are four possible canonical topologies for potential AST T: see Figures 17(b)– 17(e). However, since [ x,y,z] is an agreement triplet, only one of the four topologies exists across all input trees. Thus, AST T exists.
Further, in all the cases discussed above, the last two leaves in the IDFT of T are y and z (either y comes before z or viceversa), while x is the thirdtolast leaf. Thus, pruning y in T will result in a canonical tree where x and z are the secondtolast and last leaves in the IDFT. By definition, the resulting tree is T_{ x z }. Thus, T_{ x z } exists. Further, pruning the last leaf in T will result in either T_{ x y } (if z is the last leaf in T) or T_{ x z } (if y is the last leaf in T). In either case, ${\mathcal{E}}_{T}$ is a descendant of X, as claimed.
 3.Suppose T _{ x y } is a result of a type2 join. Thus, ψ(x)<ψ(y). Consider the following possibilities:
 (a)
T _{ y z } is a result of a type1 join (see Figure 17(f)). Thus, ψ(y)<ψ(z). Potential AST T must be obtained by grafting x in T _{ y z }. Since T must display (r,(x,y)), there is only one possibility of grafting x in T _{ y z }: x should be grafted on the edge (p _{ y },y). Thus, AST T exists. Further, since, ψ(x)<ψ(y)<ψ(z), there is only one possible canonical topology for potential AST T: see Figure 17(f). Since T has x, y, z as the thirdtolast, secondtolast and last leaf respectively in the IDFT, pruning y will result in a tree that is (a) canonical, (b) has z as the last leaf in the IDFT, and (c) has x as the secondtolast leaf in the IDFT. By definition, the resulting tree is T _{ x z } (see Figure 17(f)). Further, the topology of T _{ x z } implies that T _{ x z } results from a type1 join.
 (b)
T _{ y z } is a result of a type3 join (see Figure 17(g)). Potential AST T must be obtained by grafting x in T _{ y z }. Since T must display (r,(x,y)), there is only one possibility of grafting x in T _{ y z }: x should be grafted on the edge (p _{ y },y). Thus, AST T exists. Further, since, ψ(x)<ψ(y), there is only one possible canonical topology for potential AST T: see Figure 17(g). Since T has x, y, z as the thirdtolast, secondtolast and last leaf respectively in the IDFT, pruning y will result in a tree that is (a) canonical, (b) has z as the last leaf in the IDFT, and (c) has x as the secondtolast leaf in the IDFT. By definition, the resulting tree is T _{ x z } (see Figure 17(g)). Further, the topology of T _{ x z } implies that T _{ x z } results from a type3 join.
 (c)
T _{ y z } is a result of a type4 join (see Figure 17(h)). Potential AST T must be obtained by grafting x in T _{ y z }. Since T must display (r,(x,y)), there is only one possibility of grafting x in T _{ y z }: x should be grafted on the edge (p _{ y },y). Thus, AST T exists. Further, since, ψ(x)<ψ(y), there is only one possible canonical topology for potential AST T: see Figure 17(h). Since T has x, y, z as the thirdtolast, secondtolast and last leaf respectively in the IDFT, pruning y will result in a tree that is (a) canonical, (b) has z as the last leaf in the IDFT, and (c) has x as the secondtolast leaf in the IDFT. By definition, the resulting tree is T _{ x z } (see Figure 17(h)). Further, the topology of T _{ x z } implies that T _{ x z } results from a type4 join.
Further, in all the above cases, y and z are the secondtolast and the last leaves in T. Thus, pruning z — the rightmost leaf — in T will result in a tree that is (a) canonical, (b) has y as the last leaf in the IDFT, and (c) has x as the secondtolast leaf in the IDFT. By definition, the resulting tree is T_{ x y }. Hence, ${\mathcal{E}}_{T}$ is a descendant of ${\mathcal{E}}_{{T}_{\mathit{\text{xy}}}}$, as claimed.
 (a)
□
Proof of Lemma 2.
 1.
${\text{depth}}^{{T}_{\mathit{\text{xy}}}}\left({p}_{y}\right)>{\text{depth}}^{{T}_{\mathit{\text{xz}}}}\left({p}_{z}\right)$ : As per Theorem 1, T _{x−y z} exists as a result of a type4 join.
 2.
${\text{depth}}^{{T}_{\mathit{\text{xz}}}}\left({p}_{z}\right)>{\text{depth}}^{{T}_{\mathit{\text{xy}}}}\left({p}_{y}\right)$ : As per Theorem 1, T _{x−z y} exists as a result of a type4 join.
 3.${\text{depth}}^{{T}_{\mathit{\text{xy}}}}\left({p}_{y}\right)={\text{depth}}^{{T}_{\mathit{\text{xz}}}}\left({p}_{z}\right)$ : Consider the following subcases:
 (a)
Agreement triplet [ x,y,z] is of type (x,y,z). Thus, depth(LCA(x,y))=depth(LCA(y,z))=depth(LCA(x,z)) across all input trees. Thus, as per Theorem 1, T _{x−y z} exists as a result of a type1 join.
 (b)
Agreement triplet [ x,y,z] is of type (x,(y,z)). Thus, depth(LCA(x,y))=depth(LCA(x,z)) and depth(LCA(x,y))<depth(LCA(y,z)) across all input trees. Thus, as per Theorem 1, T _{x−y z} exist as a result of a type2 join.
 (c)
Agreement triplet [ x,y,z] is of type ((x,y),z). Thus, depth(LCA(x,y))>depth(LCA(x,z)) across all input trees. Thus, as per Theorem 1, T _{x−y z} exists as a result of a type3 join.
 (d)
Agreement triplet [ x,y,z] is of type ((x,z),y). Thus, depth(LCA(x,z))>depth(LCA(x,y)) across all input trees. Thus, as per Theorem 1, T _{x−z y} exists as a result of a type3 join.
 (a)
Thus, in each of the above cases, either T_{x−y z} or T_{x−z y} exists, as claimed. □
Proof of Lemma 3.
(Only If) An AST is enumerated by joining joining two trees in an equivalence class. Thus, the union of leaf sets of trees in an equivalence class is a subset of the union of leaf sets of trees in the parent equivalence class. Extending this reasoning, the union of leaf sets of trees in an equivalence class is a subset of the union of leaf sets of trees in any ancestor equivalence class. Thus, if ${\mathcal{E}}_{B}$ is a descendant of ${\mathcal{E}}_{A}$, ${\mathcal{\mathcal{L}}}_{B}$ is subset of the union of leaf sets of trees in ${\mathcal{E}}_{A}$. Further, every tree in ${\mathcal{E}}_{A}$ has A as its prefix. Thus, for every $\ell \in \{{\mathcal{\mathcal{L}}}_{B}\setminus {\mathcal{\mathcal{L}}}_{A}\}$, T_{ a ℓ } must exist.
(If) For every $\{i,j\}\in \{{\mathcal{\mathcal{L}}}_{B}\setminus {\mathcal{\mathcal{L}}}_{A}\}$, T_{ a i } and T_{ a j } exist (if condition of the claim), and [ a,i,j] is an agreement triplet (because $\{a,i,j\}\in {\mathcal{\mathcal{L}}}_{B}$). Thus, as per Lemma 2, either T_{a−i j} or T_{a−j i} exists. We show that there exists an $\ell \in \{{\mathcal{\mathcal{L}}}_{B}\setminus {\mathcal{\mathcal{L}}}_{A}\}$ such that for every $i\in \{{\mathcal{\mathcal{L}}}_{B}\setminus \{{\mathcal{\mathcal{L}}}_{A}\cup \ell \left\}\right\}$, T_{a−ℓ i} exists. If this is not the case, there exists a sequence of leaves $({\ell}_{0},{\ell}_{1},\dots {\ell}_{n})\in \{{\mathcal{\mathcal{L}}}_{B}\setminus {\mathcal{\mathcal{L}}}_{A}\}$ such that ${T}_{a{\ell}_{0}{\ell}_{1}}$, ${T}_{a{\ell}_{1}{\ell}_{2}}$, …, ${T}_{a{l}_{n1}{l}_{n}}$, ${T}_{a{l}_{n}{l}_{0}}$ exist. Since ${T}_{a{l}_{0}{l}_{1}}$ and ${T}_{a{l}_{1}{l}_{2}}$ exist, and [l_{0},l_{1},l_{2}] is an agreement triplet (because $\{{l}_{0},{l}_{1},{l}_{2}\}\in {\mathcal{\mathcal{L}}}_{B}$), as per Lemma 1, AST ${T}_{a{l}_{0},{l}_{2}}$ exists. Extending this reasoning, it can be shown that ${T}_{a{l}_{0}\mathit{\text{ln}}}$ exists — a contradiction because ${T}_{x{l}_{n}{l}_{0}}$ already exists. Thus, there exists an $\ell \in \{{\mathcal{\mathcal{L}}}_{B}\setminus {\mathcal{\mathcal{L}}}_{A}\}$ such that for every $i\in \{{\mathcal{\mathcal{L}}}_{B}\setminus \{{\mathcal{\mathcal{L}}}_{A}\cup \ell \left\}\right\}$, T_{a−ℓ i} exists. By definition, each such T_{a−l i} belongs to ${\mathcal{E}}_{{T}_{\mathit{\text{al}}}}$, and ${\mathcal{E}}_{{T}_{\mathit{\text{al}}}}$ is a child of A. Extending the same reasoning, it can be shown that there exists a sequence of ASTs (T_{1},T_{2}...), where T_{1}=A, such that ${\mathcal{E}}_{{T}_{i+1}}$ is a child of ${\mathcal{E}}_{i}$ and ${\mathcal{\mathcal{L}}}_{{T}_{i+1}}\setminus {\mathcal{\mathcal{L}}}_{{T}_{i}}$ is a leaf in $\{{\mathcal{\mathcal{L}}}_{A}\setminus {\mathcal{\mathcal{L}}}_{B}\}$. By definition, the last AST in the sequence is B. Thus, ${\mathcal{E}}_{B}$ is a descendant of ${\mathcal{E}}_{A}$. □
Proof of Lemma 4.
 1.
T _{ y ℓ } is a result of a type1 join. There exists only one possible canonical topology for T: the one corresponding to Figure 17(f) (replace z with ℓ in tree T).
 2.
T _{ y ℓ } is a result of a type2 join. There exists four possible canonical topologies for T: the ones corresponding to Figure 17(b)—17(e) (replace z with ℓ in tree T).
 3.
T _{ y ℓ } is a result of a type3 join. There exists only one possible canonical topology for T: the one corresponding to Figure 17(g) (replace z with ℓ in tree T).
 4.
T _{ y ℓ } is a result of a type4 join. There exists only one possible canonical topology for T: the one corresponding to Figure 17(h) (replace z with ℓ in tree T).
 1.
Both T ^{ a } and T ^{ b } belong to ${\mathcal{E}}_{{T}_{\mathit{\text{xy}}}}$. Since [ y,a,b] is an agreement triplet, by Lemma 2, there exists an AST on leaf set ${\mathcal{\mathcal{L}}}_{{T}_{\mathit{\text{xy}}}}\cup \{a,b\}$. Thus, [ x,a,b] is an agreement triplet.
 2.Both T ^{ a } and T ^{ b } do not belong to ${\mathcal{E}}_{{T}_{\mathit{\text{xy}}}}$. Without loss of generality, let T ^{ a } belong to ${\mathcal{E}}_{{T}_{\mathit{\text{xa}}}}$, i.e., it corresponds to the topology in Figure 17(e) (replace z with a in tree T). Thus, agreement triplet [x,y,a] is of type ((x,a),y) and ψ(x)<ψ(a). Consider potential AST T’ on leaf set ${\mathcal{\mathcal{L}}}_{{T}_{\mathit{\text{xy}}}}\cup \{a,b\}$ that displays both T ^{ a } and T ^{ b }. Since, the topology T ^{ a } is known, the topology of T’ depends on the topology of T ^{ b }. Consider the following cases. In the subsequent discussion, let p _{ x }, p _{ y }, p _{ a } and p _{ b } denote the parent of x, y, a and b respectively.
 (a)
T ^{ b } corresponds to the topology in Figure 17(f) (replace z with b in tree T). Potential AST T’ must be obtained by grafting a in T ^{ b }. Since T’ must display ((x,a),y), there is only one possibility of grafting a in T ^{ b }: a should be grafted on the edge (p _{ x },x). Thus, T’ exists. Considering ψ(x)<ψ(a), the canonical topology for AST T’ is shown in Figure 18(a).
 (b)
T ^{ b } corresponds to the topology in Figure 17(b) (replace z with b in tree T). Potential AST T’ must be obtained by grafting a in T ^{ b }. Since T’ must display ((x,a),y), there is only one possibility of grafting a in T ^{ b }: a should be grafted on the edge (p _{ x },x). Thus, T’ exists. Considering ψ(x)<ψ(a), the canonical topology for AST T’ is shown in Figure 18(b).
 (c)
T ^{ b } corresponds to the topology in Figure 17(c) (replace z with b in tree T). Potential AST T’ must be obtained by grafting a in T ^{ b }. Since T’ must display ((x,a),y), there is only one possibility of grafting a in T ^{ b }: a should be grafted on the edge (p _{ x },x). Thus, T’ exists. Considering ψ(x)<ψ(a), the canonical topology for AST T’ is shown in Figure 18(c).
 (d)
T ^{ b } corresponds to the topology in Figure 17(d) (replace z with b in tree T). Potential AST T’ must be obtained by grafting a in T ^{ b }. Since T’ must display ((x,a),y), there is only one possibility of grafting a in T ^{ b }: a should be grafted on the edge (p _{ x },x). Thus, T’ exists. Considering ψ(x)<ψ(a), the canonical topology for AST T’ is shown in Figure 18(d).
 (e)
T ^{ b } corresponds to the topology in Figure 17(e) (replace z with b in tree T). Thus, ψ(x)<ψ(b). Since, both T ^{ a } and T ^{ b } correspond to the topology in Figure 17(e), without loss of generality, let ψ(a)<ψ(b). Potential AST T’ must be obtained by grafting a in T ^{ b } and must display ((x,a),y). Since ψ(x)<ψ(a)<ψ(b), there are four possible canonical topologies for T’; see Figure 19(a). However, [ y,a,b] is an agreement triplet, thus, only one of the four possible topologies exits across all input trees Thus, T’ exists.
 (f)
T ^{ b } corresponds to the topology in Figure 17(g) (replace z with b in tree T). Potential AST T’ must be obtained by grafting a in T ^{ b }. Since T’ must display ((x,a),y), there is only one possibility of grafting a in T ^{ b }: a should be grafted on the edge (p _{ x },x). Thus, T’ exists. Considering ψ(x)<ψ(a), the canonical topology for AST T’ is shown in Figure 19(b).
 (g)
T ^{ b } corresponds to the topology in Figure 17(h) (replace z with b in tree T). Potential AST T’ must be obtained by grafting a in T ^{ b }. Since T’ must display ((x,a),y), there is only one possibility of grafting a in T ^{ b }: a should be grafted on the edge (p _{ x },x). Thus, T’ exists. Considering ψ(x)<ψ(x), the canonical topology for AST T’ is shown in Figure 19(c).
 (a)
Thus, in each of the above cases T’ exists. Thus, [ x,a,b] is an agreement triplet.
This completes the proof. □
Declarations
Acknowledgments
This work was supported in part by National Science Foundation grant DEB0829674. The authors thank Dr. Nicholas D. Pattengale for sharing the set of bootstrapped trees. They also thank Dr. Tamer Kahveci and Avinash Ramu for sharing their implementation that mines MFSTs with maximum leaves and for discussions on their work.
Authors’ Affiliations
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